Check if a given binary tree is symmetric.
Solution:
public boolean recurseSymmetry(Node<AnyType> left, Node<AnyType> right ){
if(left == null || right == null) return left==right;
else
return left.value == right.value &&
recurseSymmetry(left.left, right.right) &&
recurseSymmetry(left.right, right.left);
}
Complexity:
time - O(n)Links and credits:
space - O(n) (for recursion stack)
http://www.careercup.com/question?id=20884671
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